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> Macroinstructions > Question about sizeof. inside match |
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hopcode 09 Jul 2008, 17:32
After i have read this thread, i have found the solution for this code, that compiles good now.
Code: macro makestructB param@struct { match paramB:structB,param@struct \{ paramB structB db sizeof\#.\#structB dup (90) ; <-- ----------Why so ? \} } macro makestructA paramA,structA { paramA structA db sizeof.#structA dup (90) } makestructA rect1,RECT makestructB rect2:RECT .... But I cannot understand why i must write, inside a match, db sizeof\#.\#structB dup (90) escaping, if i do not err, not only structB but the "." too ? in spite of, for example as in makestructA, the simpler form db sizeof.#structA dup (90) . Please, help. Speak to me simple as it was to a baby. because i think that it is important and i would like to understand it. Lot of thanks. FASM,FASM,FASM  |
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09 Jul 2008, 17:32 |
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revolution 10 Jul 2008, 00:33
It is sufficient to put:
Code: db sizeof.\#structB dup (90) |
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10 Jul 2008, 00:33 |
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hopcode 10 Jul 2008, 03:53
Right revolution!. My error !!
I was about to reinterpret all Fasm cryptomanual!!! 
Now i have the solution. You can find an application with this solution in this thread. Bye, and a lot, lot of thanks... ... hopcode[mrk] |
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10 Jul 2008, 03:53 |
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