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revolution 07 Oct 2006, 10:06
Quote: I would like to know what is returned in eax after the final subtraction. |
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07 Oct 2006, 10:06 |
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ManOfSteel 07 Oct 2006, 10:44
Ok, thanks. Just what I thought. So basically, one could just use the Addr3 label automatically instead of doing these computations, right?
like: Code: Addr3: mov byte [Addr3],'w' instead of: Code:
call Addr2
Addr1:
<some code>
Addr2: pop eax
sub eax,(Addr1 - Addr3)
<some code>
Addr3:
mov byte [eax],'w'
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07 Oct 2006, 10:44 |
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revolution 07 Oct 2006, 11:00
Quote: one could just use the Addr3 label automatically |
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07 Oct 2006, 11:00 |
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