Hello all. I wrote myself a hard-drive temperature/model reader in C, and since I'm learning assembly, I decided to re-write it in assembly.

All has gone well, until now. I need to print a retrieved byte as an integer (like printf("value == %d\n", byte);

The retrieved byte is 0x1e, which, converted to an integer, and according to printf(), is 30. I'm reading the data into a buffer in the stack (though I can probably just put it in a register... it's one byte). So, without depending on libc's printf(), how can I print out, or convert, the byte to it's integer equivalent?

That would depend on the operating system you are on.

First, to convert the value to a string equivalent of it, use this code:


This isnt mine, I found it on this board somewhere, sorry to whoever wrote it for not putting your name here, I just never noted it down. But great code.

You would then output it using the OS-specific API.

For linux, you would use something along the lines of:


Oh, and a tip, you can find the length of the string made by the code at the top by doing:

after calling it.

Good luck,
gunblade

Thanks for the response. However, I have a few questions:

First, since it's my third day of learning/programming in assembly, could you please comment the lines? I can understand some of it, but I'm not quite sure what's totally going on.

Also, the comment says that ebx is the base... what do you mean by base? Like base-10, base-6 (hex), etc? Or something else?

Thanks for that tip, too. I was wondering how I'd do that.

Check here for a fast bin2dec routine (Terje Mathisen, GPL): http://board.flatassembler.net/topic.php?t=3924

Yeah, it should be the fastest (60 clocks) against the traditional divide_by_10_and_take_the_reminder approach where every such division takes at least 49 clocks and you need upto ten of these.