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Index > Macroinstructions > how to eval a expression before the Match?

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lilainst



Joined: 29 Jul 2004
Posts: 11
lilainst 05 Mar 2006, 08:35
For example, the following code never got matched, since the 'new' was calculated after the 'match':

Code:
rept 8 counter {
        new = counter * 4
        match =4, new {display "match it"}
}
    



Is it possible to do some match which depends on the previous expression? Thanks.
Post 05 Mar 2006, 08:35
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Tomasz Grysztar



Joined: 16 Jun 2003
Posts: 8411
Location: Kraków, Poland
Tomasz Grysztar 05 Mar 2006, 11:40
If you need calculations, use assembler, not preprocessor:
Code:
repeat 8
  new = % * 4
  if new=4
    display "..."
  end if
end repeat    
Post 05 Mar 2006, 11:40
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lilainst



Joined: 29 Jul 2004
Posts: 11
lilainst 05 Mar 2006, 23:20
In order not to bother everyone here, I didn't post all my intention in the first post. Sorry.

Actually, I wanna write a Macroinstruction to display values of some constants. Of course, there's an example in manual pages which displays 32bit value, however, I intend to write a macro which could display the value of constant in spite of its length. I wrote the following code:
Code:
macro   output value {
        display "0x"
        repeat 16  ; 64bit number
                tmp = (value shr ((% - 1) * 4))
                nybble = tmp and 0xf
                if tmp <> 0
                        if nybble > 9
                                char = 'A' + nybble - 9 - 1
                        else
                                char = '0' + nybble
                        end if
                        display char
                end if
        end repeat
}

output  0xabcdef1234567890
    


The problem is "output" macro will display the value in reverse order. As I remembered there's an example of 'append' macro in the manual, which could help build macro args, I change the code to :
Code:
list equ
macro append item
{
        match   any, list \{ list equ list, item\}
        match   , list  \{list equ item\}
}

macro   display_nybble [arg]
{
        reverse display arg
}


macro   output value {
        display "0x"
        repeat 16   ; 64bit number
                tmp = (value shr ((% - 1) * 4))
                nybble = tmp and 0xf
                if tmp <> 0
                        if nybble > 9
                                char = 'A' + nybble - 9 - 1
                        else
                                char = '0' + nybble
                        end if
                         ; append char to list
                        append char
                end if
        end repeat
}

output  0xabcdef1234567890

match params, list {display_nybble params}
    

It doesn't work either, cause the 'match' is processed before the calculations. Should I think in another way?
Thanks in advance.
Post 05 Mar 2006, 23:20
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Tomasz Grysztar



Joined: 16 Jun 2003
Posts: 8411
Location: Kraków, Poland
Tomasz Grysztar 05 Mar 2006, 23:27
The outputting code is written in the assembler's language, while the "macro" and "match" are the things of preprocessor - you cannot mix those two worlds in this way.
You should instead modify the assembler's algorithm to produce the digits in the reverse order. Replacing (% - 1) by (16 - %) should be enough in this case.
Post 05 Mar 2006, 23:27
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