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Index > Linux > How to allocate memory in Linux dynamically (like malloc)

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Ton



Joined: 06 Jan 2005
Posts: 22
Ton 10 Feb 2005, 08:30
Dear all,

In fasm I can allocate memory with e.g.
a0 rd 1024h

But how can I do this dynamically using system calls. Basically I need a
malloc(3), and free(3). I couldn't find the clue in the system call list, there is
no *alloc* there.

Best Regards,
Ton
Post 10 Feb 2005, 08:30
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Endre



Joined: 29 Dec 2003
Posts: 215
Location: Budapest, Hungary
Endre 10 Feb 2005, 12:11
You have an excellent example: Take a look into the source of fasm. You will find it.
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Tomasz Grysztar



Joined: 16 Jun 2003
Posts: 8351
Location: Kraków, Poland
Tomasz Grysztar 10 Feb 2005, 12:18
It's syscall 45, called sys_brk, which resizes the memory block allocated for your program (the program resides on the bottom of this block, and with sys_brk you just move the top of it).
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Dryobates



Joined: 13 Jul 2003
Posts: 46
Location: Poland
Dryobates 10 Feb 2005, 16:11
sys_brk is old style. Now it's preffered sys_mmap with anon mapping.

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Tomasz Grysztar



Joined: 16 Jun 2003
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Tomasz Grysztar 10 Feb 2005, 16:21
However brk syscall is common for the Linux and all BSD systems (I'm not sure about BeOS), so I preferred it.
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Ton



Joined: 06 Jan 2005
Posts: 22
Ton 10 Feb 2005, 16:52
Thanks for the pointers. Iĺl give it a try.

--
Ton
Post 10 Feb 2005, 16:52
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scientica
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Joined: 16 Jun 2003
Posts: 689
Location: Linköping, Sweden
scientica 11 Feb 2005, 12:48
there's also malloc and free in linux Smile
try: man 3 malloc
Post 11 Feb 2005, 12:48
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Dryobates



Joined: 13 Jul 2003
Posts: 46
Location: Poland
Dryobates 11 Feb 2005, 22:08
scientica wrote:
there's also malloc and free in linux Smile
try: man 3 malloc

But then he need link with libc...

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