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> Main > Method to mov [dw] to higher and lower bit of regs? |
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revolution 12 Nov 2022, 00:07
You either need a byte override to force a byte load, or change the dw definitions to db.
Code: mov dh,byte [x] mov dl,byte [y] x dw 0 y dw 0 Code: mov dh,[x] mov dl,[y] x db 0 y db 0 |
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12 Nov 2022, 00:07 |
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geekbasic@gmx.com 12 Nov 2022, 00:17
That probably would have taken me several more hours to figure out.
I was considering using db, but that would make my program more complex than using the first option you suggested. I'll give it a try.. Thank you! |
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12 Nov 2022, 00:17 |
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bitRAKE 12 Nov 2022, 02:23
Another option is to not give the label a size specification:
Code: mov dh,[x] mov dl,[y] x: dw 0 y: dw 0 |
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12 Nov 2022, 02:23 |
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revolution 12 Nov 2022, 03:50
If you want to keep the size information and also avoid any overrides then you can use label to create an alias.
Code: mov dh,[x_bytes] mov dl,[y_bytes] mov ax,[x] mov bx,[y] label x_bytes byte x dw 0 label y_bytes byte y dw 0 |
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12 Nov 2022, 03:50 |
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geekbasic@gmx.com 12 Nov 2022, 05:35
The size protection is to prevent overflowing from the data?
I'm trying to make sure I understand. |
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12 Nov 2022, 05:35 |
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revolution 12 Nov 2022, 06:05
geekbasic@gmx.com wrote: The size protection is to prevent overflowing from the data? |
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12 Nov 2022, 06:05 |
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