macro add float and int problem.

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Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 17:52

Fasmw 1.73
I try this macro but result wrong.

Code:

macro app a,b {
   ee equ add
   e2 equ eax
   if  a#_type = 2
      display 'yes'
      mov eax,[a]
   else
      display 'no;'
      cvtsi2ss xmm1,[a]
      ee equ addss
      e2 equ xmm1
   end if
   vv equ ebx
   if  b#_type = 2
      display '2yes;'
      ;mov ebx,[b]
      vv equ [b]
   else
      display '2no;'
      cvtsi2ss xmm2,[b]
      vv equ xmm2
   end if
   ee e2,vv

}    

p1 dd 10.0
p1_type = 4
p2 dd 2
p2_type = 2

app p1,p2

I expected addss xmm1,[b]
But IDA Pro show addss xmm1,xmm2

11 Oct 2022, 17:52

macomics

Joined: 26 Jan 2021
Posts: 1071
Location: Russia

macomics 11 Oct 2022, 17:58

Code:

ee eq addss
e2 equ xmm1

Code:

vv equ xmm2

Code:

ee e2,vv ; addss xmm1, xmm2

You got what you wrote yourself. The macro works correctly.

11 Oct 2022, 17:58

Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 18:08

But why ?
if b#_type = 2 ;i expect this
display '2yes;'
;mov ebx,[b]
vv equ [b]
else ;else must work if b#_type not 2
display '2no;'
cvtsi2ss xmm2,[b]
vv equ xmm2 ;but get this ! Why ?
end if

11 Oct 2022, 18:08

macomics

Joined: 26 Jan 2021
Posts: 1071
Location: Russia

macomics 11 Oct 2022, 18:11

Because if is handled by an assembler, and equ is handled by a preprocessor. First, everything related to the preprocessor is calculated, and then the assembler starts working. Macro substitution is also handled by the preprocessor.

Last edited by macomics on 11 Oct 2022, 18:13; edited 1 time in total

11 Oct 2022, 18:11

Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 18:12

And how fix this ?

11 Oct 2022, 18:12

macomics

Joined: 26 Jan 2021
Posts: 1071
Location: Russia

macomics 11 Oct 2022, 18:14

Try using match

11 Oct 2022, 18:14

Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 18:16

Quote:

using match

I'm in shoke Smile

I do more simple

Code:

macro app a,b {
   if  a#_type = 2
       cvtsi2ss xmm0,[a]
   else
      movss xmm0,[a]
   end if
   if  b#_type = 2
       cvtsi2ss xmm1,[b]
   else
      movss xmm1,[b]
   end if
   addss xmm0,xmm1
}

11 Oct 2022, 18:16

Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 18:44

How do somthing like this ? Fasm get me error

Code:

if  a#_type = b#_type = 4
       display 'rt;'
   end if

Its right variant ?

Code:

if  a#_type = b#_type & a#_type = 4 
display 'rt;'
end if

11 Oct 2022, 18:44

macomics

Joined: 26 Jan 2021
Posts: 1071
Location: Russia

macomics 11 Oct 2022, 19:03

Code:

if a#_type = 4 & b#_type = 4
  display "Hello",13,10
end if

11 Oct 2022, 19:03

Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 11 Oct 2022, 19:07

Thanks. Work

Code:

macro app a,b,c {
   if  a#_type = 4 & b#_type = 4
       movss xmm0,[a]
       addss xmm0,[b]
   end if

   if  a#_type = 2 & b#_type = 2
       mov eax,[a]
       add eax,[b]
   end if

    if  a#_type = 4 & b#_type = 2
       cvtsi2ss xmm0,[b]
       addss xmm0,[a]
   end if
if  a#_type = 2 & b#_type =  4
       cvtsi2ss xmm0,[a]
       addss xmm0,[b]
   end if

   if    c#_type = 4
   movss [c],xmm0
   else
        cvtss2si eax,xmm0
       mov [c],eax
   end if

}

11 Oct 2022, 19:07

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