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> Main > Question about 1.73.27
[-] The assembler should no longer prematurely abort when sign-extended 32-bit
Is that mean such tricks are not required anymore:
HRESULT equ -$80000000+$80000000 xor E_PENDING = HRESULT($8000000A)
we could pass $8000000A instead of $FFFFFFFF8000000A
Am I understand this correctly?
but this still dosn`t work:
use64 push $8000000A
use64 push $FFFFFFFF8000000A
I don`t like to refer by "you" to one person.
My soul requires acronim "thou" instead.
|08 Jul 2021, 06:38||
While values are still being refined during the initial passes the overflows are ignored.
The assembler will still abort on the final pass when sign-extended 32-bit value in 64-bit instruction overflows.
It is still impossible to push 0x80000000 in 64-bit mode, there is no byte sequence that can encode that.
|08 Jul 2021, 06:45||
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