Question about 1.73.27

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ProMiNick

Joined: 24 Mar 2012
Posts: 817
Location: Russian Federation, Sochi

ProMiNick 08 Jul 2021, 06:38

Quote:

[-] The assembler should no longer prematurely abort when sign-extended 32-bit
value in 64-bit instruction overflows during intermediate passes.

Is that mean such tricks are not required anymore:

Code:

HRESULT equ -$80000000+$80000000 xor
E_PENDING                       = HRESULT($8000000A)

we could pass $8000000A instead of $FFFFFFFF8000000A

Am I understand this correctly?

but this still dosn`t work:

Code:

use64
push $8000000A

required

Code:

use64
push $FFFFFFFF8000000A

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08 Jul 2021, 06:38

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20522
Location: In your JS exploiting you and your system

revolution 08 Jul 2021, 06:45

While values are still being refined during the initial passes the overflows are ignored.

The assembler will still abort on the final pass when sign-extended 32-bit value in 64-bit instruction overflows.

It is still impossible to push 0x80000000 in 64-bit mode, there is no byte sequence that can encode that.

08 Jul 2021, 06:45

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