Maybe a dumb question, but I do not completely understand what happens inside when I define the same local symbol many times.



Do I end up having two memory regions allocated for the symbol?

Looks like no, as

just displays two '1's

Each CALM instruction has its own namespace, and LOCAL just forces a symbol to be considered present in that namespace, to prevent looking for global definitions. Note that if there is no global (meaning: in any of the parent namespaces) symbol defined with such name, then the one in the instruction's own namespace is going to be used anyway (even if you do not use LOCAL). What CALM's LOCAL actually does is that it gives the symbol a defined but unusable value, to force the symbol look-up to stop at the local level instead of going to the parent namespaces.