Generate code by condition

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Jin X

Joined: 06 Mar 2004
Posts: 133
Location: Russia

Jin X 16 Jan 2021, 18:47

Code:

org     $100

macro get_v rv
{
  local reg, ofs, init
  reg equ rv
  ofs = 0
  init = 1

  match r==val, rv \{
    reg equ r
    if (val)-128 <= v & (val)+127 >= v
      init = 0
      ofs = v-val
    end if
  \}

  if init
    mov reg,v
  end if

  mov ax,[reg+ofs]
}

get_v bx+si=$100
v = $

Result:

Code:

get_v bx+si=$100
1.fasm [17] get_v [13]:
    mov reg,v
processed: mov bx+si,v
error: invalid operand.

What should I change to make this work?
If works perfect with argument bx=$100 (and doesn't generate mov bx,v).

16 Jan 2021, 18:47

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20594
Location: In your JS exploiting you and your system

revolution 16 Jan 2021, 22:30

What do you want it to do?

16 Jan 2021, 22:30

Jin X

Joined: 06 Mar 2004
Posts: 133
Location: Russia

Jin X 17 Jan 2021, 00:23

I want to check parameter and if it satisfies the conditions, then use it (or another parameter) in instruction.
The problem is that if check fails, instruction will be illegal (mov reg,v will be illegal if reg is bx+si but it shouldn't be generated if parameter is set to e.g. bx+si=$100 and v is near to $100).
Compiler raises an error in that case (if condition contains refer to variable), even though instruction shouldn't be generated!
I can't use match for condition, because it contain math calculations.

17 Jan 2021, 00:23

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20594
Location: In your JS exploiting you and your system

revolution 17 Jan 2021, 03:30

Please show the output you expect:

Code:

get_v bx=$100 ; generate what code?
get_v bx+si=$100 ; generate what code?

17 Jan 2021, 03:30

Calanor

Joined: 19 Jul 2015
Posts: 45
Location: Sweden

Calanor 17 Jan 2021, 08:00

Jin X: v is assigned a value after the macro call. If you swap the last two lines, it should work.

17 Jan 2021, 08:00

Jin X

Joined: 06 Mar 2004
Posts: 133
Location: Russia

Jin X 18 Jan 2021, 18:32

revolution,

Code:

mov ax,[bx+v-$100]
mov ax,[bx+si+v-$100]

Using get_v and get_v bx=$1000 should generate:

Code:

mov bx,v
mov ax,[bx]

Calanor wrote:

Jin X: v is assigned a value after the macro call. If you swap the last two lines, it should work.

Thanks. But I don't want to swap. I want it to work in any case.

18 Jan 2021, 18:32

bitRAKE

Joined: 21 Jul 2003
Posts: 4211
Location: vpcmpistri

bitRAKE 18 Jan 2021, 20:02

I'm still having trouble understanding fully your desired output, but perhaps:

Code:

org     $100

macro get_v rv {
  local modreg, ofs

  match ,rv \{
    mov bx,v
  \}

  match any,rv \{
    modreg equ rv
    ofs = 0
    match r==val, rv \\{
      modreg equ r
      if (val)-128 <= v & (val)+127 >= v
        ofs = v-val
      end if
    \\}
    mov ax,[modreg+ofs]
  \}
}

get_v bx+si=$100
v = $

Baking the BX register within the macro might not be desired, but I can see no other way given your implied use.

_________________
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18 Jan 2021, 20:02

Calanor

Joined: 19 Jul 2015
Posts: 45
Location: Sweden

Calanor 18 Jan 2021, 20:05

OK, I think I might have misunderstood what you were trying to do. Well, try replacing "mov reg, v" with "mov word[reg], v".

18 Jan 2021, 20:05

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