apply to EQU token f ?

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Roman

Joined: 21 Apr 2012
Posts: 1878

Roman 01 Sep 2020, 06:51

I try this and work

Code:

a = 3
b = a+2
c = b*a +4
z1 EQU c
mov eax,z1  ;i get 19

I try this and this work too !

Code:

a = 3
b = a+2
c = b*a +4
z1 EQU c,a,b,24
zdt dd z1  ;i get 19,3,5,24

But how apply to z1 f ?
And get 19f its equal 19.0 float value
And get in MyDat dd z1f

01 Sep 2020, 06:51

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20526
Location: In your JS exploiting you and your system

revolution 01 Sep 2020, 07:06

You can't mix preprocessor # with assembler =.

So this can't work:

Code:

a=1
z equ a,2
match vals,z {
        irp val,vals \{
                dd val\#f  ; error: undefined symbol 'af'
        \}
}

Because the symbol 'a' is not defined when the '#' is processed.

01 Sep 2020, 07:06

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