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 Index > Main > How create float structure ? Lets say df.
Author
Roman

Joined: 21 Apr 2012
Posts: 1777
Roman 20 Jan 2019, 09:52
Fasm 1.73 have db, dw, dd ,dq, du
I want create df macro or struct. I'm so tired write after digits '.0'
Code:
```df 1,2,3,34,5,26

And we get float 1.0,2.0,3.0,34.0,5.0,26.0
```

How do this ?

And i found interesting code:
Code:
```struc dt [arg] {
if arg eqtype 1.0
dt arg
else
match sign value,arg {
match =INF,value { dq \$8000000000000000 \\}
match =NaN,value { dq \$C000000000000001 \\}
dw \$7FFF - (sign \$4000 - \$4000) \}
end if }
```

I think this code write only in macro but not in struct.

Last edited by Roman on 20 Jan 2019, 21:36; edited 1 time in total
20 Jan 2019, 09:52
ProMiNick

Joined: 24 Mar 2012
Posts: 798
Location: Russian Federation, Sochi
ProMiNick 20 Jan 2019, 11:15
Roman, thou found my code.
Code:
```struc dt [arg] {
label . tword ; add this for correcteness
if arg eqtype 1.0
dt arg
else if arg eqtype 1; may be this helps
dt arg#.0
else
match sign value,arg {
match =INF,value { dq \$8000000000000000 \\}
match =NaN,value { dq \$C000000000000001 \\} ; NaN is big range of values, and it is useless in practic (Infinity useless too)
dw \$7FFF - (sign \$4000 - \$4000) \}
end if
;if thou define table it is enought, but for single tbyte may be "dw ?" needed for alignment after it
}    ```

alternative:
Code:
```Inf equ -\$4000+\$4000+\$7FFF:\$8000000000000000
NaN equ Inf or    ```

use case
Code:
`dt Inf,+Inf,-Inf,+NaN(Index),-NaN(Index); where Index - any value from 1 to \$7FFFFFFFFFFFFFFF    `

Last edited by ProMiNick on 25 Jan 2019, 08:24; edited 2 times in total
20 Jan 2019, 11:15
Roman

Joined: 21 Apr 2012
Posts: 1777
Roman 20 Jan 2019, 14:03
Yes. I found on site KalibriOS.
ProMiNick did you been on GD.ru ?
20 Jan 2019, 14:03
l4m2

Joined: 15 Jan 2015
Posts: 674
l4m2 08 Feb 2019, 04:11
Code:
```macro df [x] {
forward
dq x#.0
}     ```
Only allow take input integer
08 Feb 2019, 04:11
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