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Index > Macroinstructions > Unusual behavor

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Mike Gonta



Joined: 26 Dec 2010
Posts: 243
Mike Gonta 15 Oct 2017, 14:44
Here is a simple example macro which converts a binary number to hexadecimal text.
Code:
macro bin2hex count, data
  local digit
  repeat count
    digit = (data shr ((count * 4 - 4) - (% - 1) * 4)) and 0x0F
    digit = digit + '0'
    if digit > '9'
      digit = digit + 7
    end if
    db digit
  end repeat
end macro    
This:
Code:
  bin2hex 2, 0x55    
creates this:
Code:
55    
And this:
Code:
  bin2hex 2, (0x55 * 2)    
creates this:
Code:
AA    
However, this
Code:
  bin2hex 2, 0x55 * 2    
creates this:
Code:
0A    
fasmg and fasm.

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Post 15 Oct 2017, 14:44
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Tomasz Grysztar



Joined: 16 Jun 2003
Posts: 8359
Location: Kraków, Poland
Tomasz Grysztar 15 Oct 2017, 15:02
Remember that macro parameters are just a simple substitution of text. So if you put a parameter into an expression, you may end up with text that computes to something else than what you imagined:
Code:
digit = (0x55 * 2 shr ((2 * 4 - 4) - (1 - 1) * 4)) and 0x0F    
If you need to use the value of a parameter in an expression, either enclose it with parentheses, or use a proxy variable.
Post 15 Oct 2017, 15:02
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Mike Gonta



Joined: 26 Dec 2010
Posts: 243
Mike Gonta 15 Oct 2017, 15:23
Tomasz Grysztar wrote:
If you need to use the value of a parameter in an expression, either enclose it with parentheses, or use a proxy variable.
Code:
value = +K    
What is the significance of the "+".

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Mike Gonta
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Post 15 Oct 2017, 15:23
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Tomasz Grysztar



Joined: 16 Jun 2003
Posts: 8359
Location: Kraków, Poland
Tomasz Grysztar 15 Oct 2017, 15:25
Mike Gonta wrote:
Code:
value = +K    
What is the significance of the "+".
If the argument is a string, "+" converts it to number.
Post 15 Oct 2017, 15:25
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