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Index > Macroinstructions > match for addition 3 or more components

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adele



Joined: 09 Jun 2017
Posts: 2
adele 09 Jun 2017, 07:21
Hi,
Here is a macro for addition four-digit numbers.
Obviously it works only for two items
But I need the code to work with forms like S=A+B+D, S=A+B+D+E, etc (with 2 or more components in temp2)
How can I change the code? Are there any ways to use recursion in macro or some other solvations?
Thank you in advance
Code:
 macro sum argument
{ 
match answer==temp1+temp2, argument
\{
        xor eax, eax
        xor ebx, ebx
        mov ax, [temp1] 
        mov bx, [temp2]
        add al, bl      
        daa 
        adc ah, 0h 
        ror ax, 8 
        ror bx, 8  
        add al, bl 
        daa 
        jnc mm 
        mov [MCR], 01h
        mm: 
        rol ax, 8       
        mov [answer],ax  
\}      
}

;*******************************************************************************

        sum S=C+D

    
Post 09 Jun 2017, 07:21
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
Posts: 20299
Location: In your JS exploiting you and your system
revolution 09 Jun 2017, 08:39
You can use irp and irps to iterate through arguments. Although with your syntax it might be tricky to separate the correct terms. You might want to consider changing the syntax, maybe like:

sum S,C,D

That would be easier to parse with a combination match and irp
Code:
macro sum result,[values] {
  common
  irp v,values \{
    mov eax,[v]
    ;...
  \}
  mov [result],eax
}    
Or you can use forward:
Code:
macro sum result,[value] {
  forward
  mov eax,[value]
  ;...
  common
  mov [result],eax
}    
Post 09 Jun 2017, 08:39
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adele



Joined: 09 Jun 2017
Posts: 2
adele 09 Jun 2017, 09:11
Yeah, I've thought about irps but I need to keep syntax
But thank you for help
Post 09 Jun 2017, 09:11
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