flat assembler
Message board for the users of flat assembler.
Index
> Heap > 60 degrees circle and triangle 
Author 

sleepsleep
am i right?
2Y mm for the 60 degrees circle? based on my logic, i would say 2Y mm is supposed result, but you all know mathematics better than me, 

07 Jul 2016, 11:06 

revolution
Yes. It is a simple scaling operation. And my website has lots and lots of examples and formulas to compute the values.


07 Jul 2016, 11:11 

sleepsleep
thanks for confirmation revolution,
my slow brain trying to figure out how to obtain pi value, 

07 Jul 2016, 11:17 

revolution
Do you mean obtain a formula for PI? Or how to find the value of PI? Either way my website can help you there also.


07 Jul 2016, 11:20 

sleepsleep
yah, but i want to discover it my self, revolution.


07 Jul 2016, 11:26 

YONG
revolution wrote: my website can help you 

07 Jul 2016, 12:54 

revolution
YONG wrote:


07 Jul 2016, 13:05 

sleepsleep
how they come to this value?
3.14159 infinite long https://en.wikipedia.org/wiki/Pi Quote: the first four of these are 3, 22/7, 333/106, and 355/113. These numbers are among the most wellknown and widely used historical approximations of the constant. but how they come up with 355/113? how they discover this? 

07 Jul 2016, 16:54 

YONG
sleepsleep wrote: but how they come up with 355/113? how they discover this? 

08 Jul 2016, 03:07 

YONG
sleepsleep wrote:  i suspect bdh equal to (x) degree circumference for circle. sleepsleep wrote:  suspect abd, dbe, cbe equal 60 degree sleepsleep wrote:  suspect hi length equal 3x de 

08 Jul 2016, 03:28 

DOS386


08 Jul 2016, 09:01 

YONG
DOS386 wrote: ERROR is better 

08 Jul 2016, 10:18 

sleepsleep
YONG wrote:
the abe green triangle should hold some important information, eg, how much to add to calculate circumference of 30 degree if we got bc length how to draw a circle, you must have center point, R and how far you want to drag from point a to point b, degree i could set the whole circle C is 360 cm, each degree equal 1 cm, 60 degree C is 60 cm but the main issue is still the "relationship" between R and degree and C but why you get 60 degree if you align 3 circles side by side? 

08 Jul 2016, 16:16 

YONG
Let the radius be 2y.
Then bc length = 2y sin 30 degrees = 2y (1/2) = y. Now, refer to your earlier diagram. 3y / bdh length = cos 30 degrees = sqrt(3) / 2 bdh length = 2 sqrt(3) y ...... (1) Circumference = 2 pi (2y) = 4 pi y 60 degrees of circumference = (1/6) (4 pi y) = (2/3) pi y ...... (2) From (1) & (2): bdh length does NOT equal 60 degrees of circumference, as sqrt(3) does not equal pi/3. 

09 Jul 2016, 03:24 

YONG
Refer to the attachment.
sin angle x = 2y / 4y = 1/2 angle x = 30 degrees That's how we get 60 degrees.


09 Jul 2016, 03:32 

< Last Thread  Next Thread > 
Forum Rules:

Copyright © 19992020, Tomasz Grysztar.
Powered by rwasa.