Yo,
I am trying to convert thsi line from masm to fasm syntax:



I tried :



but that won't do the job, how can I write this correctly?

Where is # of bits to shift?
Should it be:

Probably defaults to the constant encoding so:

sar and shr are not the same instruction since shr only shifts in 0s. sar is used when dealing with signed numbers as it will shift from the right side in 1's if negative or 0's if it's positive.

There are differences between "shift logical right" (shr) and "shift arithmetical right" (sar). See manual.

The sar instruction shifts all the bits in the destination operand to the right one bit.
I think you need to know that:
sar ax, 1 ;Signed division by 2
sar ax, 2 ;Signed division by 4
sar ax, 3 ;Signed division by 8
sar ax, 4 ;Signed division by 16
sar ax, 5 ;Signed division by 32
sar ax, 6 ;Signed division by 64
sar ax, 7 ;Signed division by 128
sar ax, 8 ;Signed division by 256
- sar truncates results toward the smaller result and idiv instruction always truncates towards zero!
- sar instruction lets you sign extend one register into another register of the same size, see this example:
mov cx, bx
sar cx, 15

I think your answer is this:

sar eax,10h
mov dword ptr [ebp-8],eax

tell me if I wrong ...