Hi,

I am new to FASM and wondered, why the virtual memory of the macroinstruction proc is defined at ebp+8.
Where does it point to (yeah, to the args, I think)? And *especially* why?

Thanks.

keenin.

I think I found out myself.

call addr:
push ebp
push eip
; = 8 Byte
mov ebp,esp
goto addr

So the virtual data of any proc lies in ebp+8.

Right?

Yes, but right order is:

call addr:
push eip
goto addr

push ebp ; This is not part of call, but part of 'ENTER' instruction.
; = 8 Byte
mov ebp,esp ; This is part of ENTER too.

For more detailed description of ENTER instruction look at Intel manual.

Regards

Thanks a lot.

Where can I find the Intel manual?

www.intel.com

http://www.intel.com/design/pentium/manuals/