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Index > Windows > Write modulo result

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TmX



Joined: 02 Mar 2006
Posts: 841
Location: Jakarta, Indonesia
TmX 05 Sep 2012, 15:48
I tried to calculate the result of modulo operation, let's say 1234 mod 10

Code:
format PE console 4.0
entry main

include 'win32a.inc'

section '.data' data readable writeable
num1 dd 1234
num2 dd 10
fmt db "%d", 13, 10, 0

section '.code' code readable executable
main:
        xor edx, edx
        mov ebx, num1
       mov ecx, num2
       div ecx
     cinvoke printf, fmt, edx
    invoke ExitProcess, 0
       
section '.idata' import data readable
library kernel32,'kernel32.dll', msvcrt,'msvcrt.dll'
import kernel32, ExitProcess,'ExitProcess'
import msvcrt, printf, 'printf'    


Why is the output of the code 4101638, not 4?
Post 05 Sep 2012, 15:48
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AsmGuru62



Joined: 28 Jan 2004
Posts: 1637
Location: Toronto, Canada
AsmGuru62 05 Sep 2012, 16:11
MOVE EAX,NUM1
Post 05 Sep 2012, 16:11
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TmX



Joined: 02 Mar 2006
Posts: 841
Location: Jakarta, Indonesia
TmX 06 Sep 2012, 06:08
Still yields the wrong result... :/
Post 06 Sep 2012, 06:08
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sinsi



Joined: 10 Aug 2007
Posts: 790
Location: Adelaide
sinsi 06 Sep 2012, 06:26
Brackets.
Post 06 Sep 2012, 06:26
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TmX



Joined: 02 Mar 2006
Posts: 841
Location: Jakarta, Indonesia
TmX 06 Sep 2012, 08:02
You mean like this?

Code:
xor edx, edx
mov eax, num1
mov ecx, num2
div ecx
cinvoke printf, fmt, [edx]    


The output is 1234.
The reminder of a DIV operation is stored in EDX, right?
http://css.csail.mit.edu/6.858/2011/readings/i386/DIV.htm
Post 06 Sep 2012, 08:02
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
Posts: 20361
Location: In your JS exploiting you and your system
revolution 06 Sep 2012, 08:05
num1 is a pointer. But we assume you actually want the number stored at num1, is that correct? If so then:
Code:
mov eax,[num1]    
Post 06 Sep 2012, 08:05
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AsmGuru62



Joined: 28 Jan 2004
Posts: 1637
Location: Toronto, Canada
AsmGuru62 06 Sep 2012, 10:24
And brackets on num2 also.
Post 06 Sep 2012, 10:24
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TmX



Joined: 02 Mar 2006
Posts: 841
Location: Jakarta, Indonesia
TmX 06 Sep 2012, 15:13
Code:
xor edx, edx
mov eax, [num1]
mov ecx, [num2]
div ecx
cinvoke printf, fmt, edx
invoke ExitProcess, 0    


works as expected. thanks Very Happy
Post 06 Sep 2012, 15:13
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