Hi everyone.

I asked this question at the end of a thread that died, so I figured I should try it one more time.

If the dl register holds a number in ASCII, how can I turn it into a number? For example, if it holds '3', and I add 10 to it, I get '=' and not 13.

Is it perhaps how I am displaying it? I am using:

ah = 2
int 21h

Thanks for your help!

The ascii code for '3' is 33h. So if you want to convert it to value of 3, you should decrease it by 30h.
If you have char '3', which is 33h and add 10 to it, you get 3dh, which is propably the ascii code for '=' (still can't remember the whole ascii table ). And if you want to display number 13, you have to convert it to ascii string '13'. Unless DOS can do that for you. Unfortunatly I'm not that familiar with dos.

as i know DOS can't do it, you must do it yourself

The link below has an attachment to a chm (compiled windows help file) with a map of the ascii table their Decimal, hex and binary codes.
http://board.flatassembler.net/topic.php?t=777&highlight=alonso

I Hope that it will help you!!