flat assembler
Message board for the users of flat assembler.
Index
> Main > fpu fild 
Author 

ProphetOfDoom
I think the FPU assumes that 3FFF has been added to the exponent (it's called a "biased" exponent). So to get the real exponent value, you subtract 3FFF from the exponent value your debugger is showing you. Your calculations should all work out then. (The bias is different for qwords and dwords). I got this from:
http://www.website.masmforum.com/tutorials/fptute/fpuchap2.htm#real10 

07 Mar 2011, 23:01 

b1528932
thank you, but i managed to understand it myself.
when you have a float representation SEEEEEMMMMMMMMMM its real value is equivalent to: sign tells if its + or , nothing more, just sign. E is exponent. MSB = 0, rest = 1 (0111111...) is 0. in order to convert to real number, you have to add it (depends on ammount of exponent bits). For example is you have 7 exponent bits, 0 is 0111111, 1 is 1000000, 2 is 1000001, and so on. 1 is 0111110, etc. M is mantisa. lets say exponent is 1000101 (1000101  0111111 = 110 (6)). mantisa is 011010 (22). real number is 0 * 2^6 = 0 1 * 2^5 = 32 1 * 2^4 = 16 0 * 2^3 = 0 1 * 2^2 = 4 0 * 2^1 = 0 32+16+4 = 52. sign is 0, so +52. lets check in bochs: +52 4004D000000000000000 0 100000000000100 1101000000000... exponent = 100000000000100  011111111111111 = 101 (5) mantisa = 11 1 * 2^5 = 32 1 * 2^4 = 16 0 * 2^3 = 0 1 * 2^2 = 4 0 * 2^1 = 0 0 * 2^0 = 0 0 * 2^1 = 0 0 * 2^2 = 0 0 * 2^3 = 0 0 * 2^4 = 0 ... 0 * 2^58 = 0 32 + 16 + 4 = 52 

08 Mar 2011, 10:26 

< Last Thread  Next Thread > 
Forum Rules:

Copyright © 19992020, Tomasz Grysztar. Also on GitHub, YouTube, Twitter.
Website powered by rwasa.