ok so i want to find the binary value for the instructions in je and jz that will allow me to jump as far as a 32-bit value can jump.
1) dose anyone happen to know what this value is or where i can find it?
2) can someone show me how to type it in FASM so i can find it with the debugger?

je = jz. equal = zero flag


ocnditional jumps are only relative, 1 byte ranged.
you can jump only 127 bytes ahead, or 128 backward.
Nothing else is needed, since you can either use cmovCC or jCC over jmp.
2) i would choose hex editor for this task

thanks i figured it out a while back using a debugger, you can jump further ahead than 127 and further back than 128 using the 0x0F84 je/jz instruction. you can go 2^31-1 forward and -2^31-6 backwards

the minus 6 is becuase you have to jump backwards form the end of the instruction witch is 6 bytes.

0x0F84 0x00000000

You can actually go forwards/backwards over the entire 32-bit address space. No need to worry about +ve or -ve distances, they wrap around.

You shouldn't call this a "far" jump. "far" has a specific meaning on x86; it means segment:offset. (Only unconditional jumps can be far.)

The jumps with one-byte offsets are called "short" jumps, while the jumps with two- or four-byte offsets are "long" jumps. But since they don't change the code segment, they're all still "near".