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Author 

MHajduk


09 Nov 2010, 11:35 

Tyler
Thanks man. I appreciate the time you must have taken to give such a detailed explanation.
What would make x and y dependant? By dependant, do you mean one is used in the others definition. Like y is defined in terms of x for example? Should the planes z=10x3y and z=3x+2y be tangent to z=5x^23xy+y^2? The graph I made with Maxima seems to contradict my assumption that they should be. You can see how z=10x3y crosses into the bottom of the "dip" in z=5x^23xy+y^2 to create a flat place and a slight change in color.


09 Nov 2010, 22:49 

ctl3d32
It is tangent. You see this glitch bacause your curve has too few polygons. Try increasing the number of polygons and you will see it is tangent.


09 Nov 2010, 23:14 

Tyler
clt3d32, it is a graph of a function and it's indefinite derivative. I was graphing f(x,y), d/dx f(x,y), and d/dy f(x,y) which aren't tangent. I meant to graph f(x,y) and a definite derivative for a point. I've got a function now to graph d/dx tangents but I'm having trouble with the concept of tangents in y... I post a complete graph when I've got both working(If I do...).


10 Nov 2010, 01:19 

Tyler
How 'bout now?
Is there a general form for this? Given df/dx and df/dy.


10 Nov 2010, 05:26 

MHajduk
Some explanations are presented in the following pictures (printerfriendly PDF document you may see here ):


13 Nov 2010, 00:15 

ctl3d32
Nice! You've made me remember some calculus.


13 Nov 2010, 01:59 

DarkAlchemist
"I know dy/dx can be rewritten as d/dx y"
Wouldn't that simplify down to x/y since d resolves to 1 so we do not need d at all in that case? 

13 Nov 2010, 09:06 

Tyler
DarkAlchemist wrote: "I know dy/dx can be rewritten as d/dx y" 

13 Nov 2010, 14:55 

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