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ouadji



Joined: 24 Dec 2008
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ouadji 04 Mar 2010, 21:57

hi, Wink
Code:
format MS COFF
...
mov [esi],0A0D0A0Dh

"operand size not specified"
    

Why should I specify operand size, since I give a 32-bit operand ?
(with only "0A0Dh", I understand ... but here, with "0A0D0A0D", why ?)
There is in this case no ambiguity possible.
thank you.

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Post 04 Mar 2010, 21:57
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revolution
When all else fails, read the source


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revolution 04 Mar 2010, 22:10
What should happen here?
Code:
mov [esi],-1    
Post 04 Mar 2010, 22:10
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ouadji



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ouadji 04 Mar 2010, 22:18

yes revolution, in this case (-1), there is a ambiguity, i understand ...( byte, word, dword ?)
In this case, i'm agree with you. But with operand "0A0D0A0Dh", there is no ambiguity.
The question about operand size has no meaning

An operand whose size exceeds the word should automatically be considered a double word.
There is anyway no alternative.

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Post 04 Mar 2010, 22:18
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revolution
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revolution 04 Mar 2010, 22:22
What should happen here?
Code:
mov [esi],valueXYZ-constantABC    
Post 04 Mar 2010, 22:22
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revolution
When all else fails, read the source


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revolution 04 Mar 2010, 22:23
What about here?
Code:
use64
mov [esi],0x0a0d0a0d    
Post 04 Mar 2010, 22:23
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ouadji



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ouadji 04 Mar 2010, 22:30

"valueXYZ-constantABC"

yes revolution,
but here too there is ambiguity about the size of the result.
In my case, there is no ambiguity.
When there is no ambiguity, and the size of the operand is explicit and exceeds the word,
FASM should consider directly that this is a double word.
yes, it's a littel bit a cosmetic problem Wink ...
but this is illogical and unnecessary.

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Post 04 Mar 2010, 22:30
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ouadji



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ouadji 04 Mar 2010, 22:32

yes,
with "USE64" there is a ambiguity.
In this case, i'm agree with you too.
But in my case, there is no ambiguity.

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Post 04 Mar 2010, 22:32
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revolution
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revolution 04 Mar 2010, 22:34
It is not cosmetic, it allows for very sloppy programming. fasm should not have to guess the size. What if I want a word size but accidentally put 0xfffff? I see no error from fasm but my program crashes for unknown reasons!


Last edited by revolution on 04 Mar 2010, 22:35; edited 1 time in total
Post 04 Mar 2010, 22:34
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LocoDelAssembly
Your code has a bug


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LocoDelAssembly 04 Mar 2010, 22:34
Code:
mov [esi], SOME_CONFIGURABLE_EQUATE ; Keep compiling until someone decides to use a constant with "size ambiguity"    
(Note, the assembler and parser stages can't know where the literal came from so it can't make an special case when the constant is typed straight)
Post 04 Mar 2010, 22:34
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zhak



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zhak 04 Mar 2010, 22:35
oh, come on, ouadji. what is all about? are you too lazy to put 5 letters "dword" in front of [esi]?


Last edited by zhak on 04 Mar 2010, 22:36; edited 1 time in total
Post 04 Mar 2010, 22:35
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ouadji



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ouadji 04 Mar 2010, 22:36

Code:
mov [esi],eax
mov [esi],0A0D0A0Dh
    
in both cases, there is no ambiguity.

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Post 04 Mar 2010, 22:36
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ouadji



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ouadji 04 Mar 2010, 22:44

Quote:

Note, the assembler and parser stages can't know where the literal came from so it can't make an special case when the constant is typed straight
thank you revolution.
with this answer, I understand now.
Quote:

are you too lazy to put 5 letters "dword" in front of [esi]?
sorry, ridiculous reply that deserves no interest.

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Last edited by ouadji on 04 Mar 2010, 23:05; edited 1 time in total
Post 04 Mar 2010, 22:44
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ouadji



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ouadji 04 Mar 2010, 22:51
Quote:

It is not cosmetic, it allows for very sloppy programming. fasm should not have to guess the size. What if I want a word size but accidentally put 0xfffff? I see no error from fasm but my program crashes for unknown reasons!
indeed, it's correct, thank you.

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Post 04 Mar 2010, 22:51
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MazeGen



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MazeGen 05 Mar 2010, 07:17
ouadji wrote:

yes,
with "USE64" there is a ambiguity.
In this case, i'm agree with you too.
But in my case, there is no ambiguity.

With use64 there is no ambiguity as well, you can't move 64-bit immediate value to memory in any case.

EDIT:
Not quite true, you can't move values 80000000-FFFFFFFF to 64-bit memory operand. You can move 0-7FFFFFFF.


Last edited by MazeGen on 06 Mar 2010, 12:11; edited 1 time in total
Post 05 Mar 2010, 07:17
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Tomasz Grysztar



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Tomasz Grysztar 05 Mar 2010, 09:05
LocoDelAssembly wrote:
(Note, the assembler and parser stages can't know where the literal came from so it can't make an special case when the constant is typed straight)
Do you mean values defined with EQU here? Since for numerical values you should use the = directive anyway, and in such case assembler is pretty much capable of deciding, whether it was the literal or not.
But this still doesn't make this idea any good. I don't want people reporting bugs that "mov [esi],65536" assembles fine, but after they decrement value, it suddenly stops assembling.
Post 05 Mar 2010, 09:05
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edfed



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edfed 05 Mar 2010, 09:29
and please note that fasm is a compiler that generate a flat image of the source.
then, operand size should be specified because there are at least 3 possible sizes.

it can be a problem sometimes, but ones you are used to this problem, it is no longer a problem.

Code:
mov dword[esi+eax*4],0
    
Post 05 Mar 2010, 09:29
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ouadji



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ouadji 05 Mar 2010, 09:40

Quote:

from Tomasz Grysztar :

I don't want people reporting bugs that "mov [esi],65536" assembles fine,
but after they decrement value, it suddenly stops assembling
indeed, this is right too !

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Post 05 Mar 2010, 09:40
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LocoDelAssembly
Your code has a bug


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LocoDelAssembly 05 Mar 2010, 15:20
Tomasz Grysztar wrote:
Do you mean values defined with EQU here?
Yes, that meant that it can't know whether it came from an equate or an in-place literal. I used that example to remove the chances of anyone saying "but fasm could know it by keeping track of how the variable was assigned".
Post 05 Mar 2010, 15:20
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baldr



Joined: 19 Mar 2008
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baldr 05 Mar 2010, 17:47
This problem looks similar to signed vs. unsigned contradiction:
Code:
a = 1 shl 63 - 1; 0x7FFF'FFFF'FFFF'FFFF
b = a+1
if b>a
  display "b>a", 13, 10
else
  display "b<=a", 13, 10
end if
if b-a>0
  display "b-a>0", 13, 10
else
  display "b-a<=0", 13, 10
end if    
Not a big surprise for those who are familiar with FASM internals, though.
Post 05 Mar 2010, 17:47
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edemko



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edemko 05 Mar 2010, 18:34
Never thought how fasm does number comparison.., it is signed.
b-a = 10b - 01b = 01b which is unsigned.
All is fine.
Post 05 Mar 2010, 18:34
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