Use an argument passed to a macro to name another macro?

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Azu

Joined: 16 Dec 2008
Posts: 1159

Azu 24 Dec 2009, 05:00

What am I doing wrong?

Code:

macro      foobar  instruction,args{
      \macro instruction,args{
              instruction     args
                if defined arg1
                     display arg1
                end if
      \}
}
foobar    mov,<arg1*,arg2*>
mov  eax,1
ret

I also tried it like this;

Code:

macro      foobar  instruction,args{
      \macro `instruction,`args{
            `instruction    `args
               if defined arg1
                     display arg1
                end if
      \}
}
foobar    mov,<arg1*,arg2*>
mov  eax,1
ret

Please help..

_________________

24 Dec 2009, 05:00

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20627
Location: In your JS exploiting you and your system

revolution 24 Dec 2009, 05:11

Code:

macro   foobar  instruction,args{
        macro  instruction [args] \{
         \common
                instruction     args
                ;if defined arg1
                ;        display arg1
                ;end if
        \}
}
foobar  mov,<arg1,arg2>
mov     eax,1
ret

24 Dec 2009, 05:11

Azu

Joined: 16 Dec 2008
Posts: 1159

Azu 24 Dec 2009, 05:56

Thank you

_________________

24 Dec 2009, 05:56

Azu

Joined: 16 Dec 2008
Posts: 1159

Azu 25 Dec 2009, 05:31

What is the correct way to use forward when constructing a macro?

Code:

macro   foobar  instruction,args,[forwardMe]{ 
        macro  instruction [args] \{ 
                \common 
                instruction     args 
forward
                instruction     forwardme
common
                ;if defined arg1 
                ;        display arg1 
                ;end if 
        \} 
} 
foobar  mov,<arg1,arg2>,ret,int3
mov     eax,1 
ret

Doesn't compile Confused

_________________

25 Dec 2009, 05:31

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20627
Location: In your JS exploiting you and your system

revolution 25 Dec 2009, 05:35

Did you mean:

Code:

macro   foobar  instruction,args,[forwardMe]{ 
common
        macro  instruction [args] \{ 
                \common 
                instruction     args 
forward
                forwardMe
common
                ;if defined arg1 
                ;        display arg1 
                ;end if 
        \} 
} 
foobar  mov,<arg1,arg2>,ret,int3
mov     eax,1 
ret

25 Dec 2009, 05:35

Azu

Joined: 16 Dec 2008
Posts: 1159

Azu 25 Dec 2009, 05:47

Oops

That was stupid of me too lol. But the problem I was having in my code was I used forward somewhere else and forgot to put a common after it. So it was trying to make the whole macro for each extra thing on the end. x_x

_________________

25 Dec 2009, 05:47

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