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Index > Compiler Internals > Conditional defines?

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Azu



Joined: 16 Dec 2008
Posts: 1160
Azu
This doesn't compile. Sad

Please tell me how to fix it..

Code:
if foo eq      1
   bar =   "blah"
else if foo eq      2
   bar =   1,2,3
else
       bar =   0
end if

foo  equ     2
db bar    
Post 19 Aug 2009, 08:03
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shoorick



Joined: 25 Feb 2005
Posts: 1605
Location: Ukraine
shoorick
maybe place foo equ 2 before if
Post 19 Aug 2009, 09:22
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Azu



Joined: 16 Dec 2008
Posts: 1160
Azu
Hmm. Actually.. it does compile in the example I gave. But it compiles wrong (to 0x0 instead of 0x010203). If I move the equ to the top it doesn't compile at all. Why is this? I thought that equs were parsed before ifs (which is why I use = instead of equ to set bar).. but were that the case it wouldn't matter whether the "foo equ 2" was at the top or bottom.


Now I'm even more confused. Confused
Post 19 Aug 2009, 09:28
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
Posts: 17270
Location: In your JS exploiting you and your system
revolution
You can't define symbols later in the source. This doesn't work:
Code:
display foo
foo     equ     1    


Also you can't assign bar = "blah", you will need to use bar equ "blah". This mean that you also have to use match to process the bar equ.
Code:
foo equ 2
bar equ   0
match foo,1 {bar equ "blah"}
match foo,2 {bar equ 1,2,3}
db bar    
Post 19 Aug 2009, 12:43
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Azu



Joined: 16 Dec 2008
Posts: 1160
Azu
Thanks, but it doesn't work.

Code:
foo equ 2 
bar equ   0 
match foo,2 {bar equ 1,2,3} 
match foo,1 {bar equ "blah"} 
db bar    
Outputs "blah". Sad




Code:
bar equ   0 
match foo,2 {bar equ 1,2,3} 
match foo,1 {bar equ "blah"} 
db bar    
Shouldn't even compile.. but outputs "blah". Sad




Please help.. the method you posted has exactly the same problems as the one I originally posted..
Post 19 Aug 2009, 21:20
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LocoDelAssembly
Your code has a bug


Joined: 06 May 2005
Posts: 4633
Location: Argentina
LocoDelAssembly
Code:
foo equ 2
bar equ 'INVALID'
match =2,foo {bar equ '1','2','3'}
match =1,foo {bar equ "blah"}
display bar    
Post 19 Aug 2009, 21:47
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Azu



Joined: 16 Dec 2008
Posts: 1160
Azu
Thank you Very Happy it works.
Post 19 Aug 2009, 21:50
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