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jInuQ

Joined: 26 Jun 2003
Posts: 48
Location: USA - NV

jInuQ 14 Mar 2004, 12:27

I am converting some C code to assembly. Can anyone tell me if this is on the right track?

Code:

proc _vorbis_apply_window, d, window_p, blocksizes, lW, W, nW
window rd 2
n  rq 1
ln rq 1
rn rq 1
leftbegin  rq 1
leftend    rq 1
rightbegin rq 1
rightend   rq 1
i rd 1
p rd 1
enter

        lea eax,     [window]
        mov eax,     [window_p]
        mov [eax+4], [window_p+4]

        return

;void _vorbis_apply_window(ogg_int32_t *d,const void *window_p[2],
;                          long *blocksizes,
;                          int lW,int W,int nW){

;  LOOKUP_T *window[2]={window_p[0],window_p[1]};
;  long n=blocksizes[W];
;  long ln=blocksizes[lW];
;  long rn=blocksizes[nW];

;  long leftbegin=n/4-ln/4;
;  long leftend=leftbegin+ln/2;

;  long rightbegin=n/2+n/4-rn/4;
;  long rightend=rightbegin+rn/2;

;  int i,p;

;  for(i=0;i<leftbegin;i++)
;    d[i]=0;

;  for(p=0;i<leftend;i++,p++)
;    d[i]=MULT31(d[i],window[lW][p]);

;  for(i=rightbegin,p=rn/2-1;i<rightend;i++,p--)
;    d[i]=MULT31(d[i],window[nW][p]);

;  for(;i<n;i++)
;    d[i]=0;
;

_________________
jInuQ

"Perfection is achieved, not when there is nothing more to add, but when there is nothing left to take away."
- Antoine de Saint Exupery

14 Mar 2004, 12:27

gorshing

Joined: 27 Jul 2003
Posts: 72
Location: Okla, US

gorshing 15 Mar 2004, 14:52

I believe that a long is only four bytes long, so I would change n, ln, rn, leftbegin, leftend, rightbegin, rightend to dword. An easy way to check that would be to output sizeof(long) from a C program.

And

Code:

mov eax,     [window_p]

Should be

Code:

mov [eax],     [window_p]

Or am I wrong?

_________________
gorshing

15 Mar 2004, 14:52

jInuQ

Joined: 26 Jun 2003
Posts: 48
Location: USA - NV

jInuQ 15 Mar 2004, 18:57

yeah, a long on my box is 4. Surprised

This is how I understand the whole braket thing with regard to registers.
Am I confused?

Code:

;This moves 15 to eax
    mov eax, 15

; And this moves  the dword pointed to by eax to ecx
    mov [ecx], [eax]

_________________
jInuQ

"Perfection is achieved, not when there is nothing more to add, but when there is nothing left to take away."
- Antoine de Saint Exupery

15 Mar 2004, 18:57

roticv

Joined: 19 Jun 2003
Posts: 374
Location: Singapore

roticv 15 Mar 2004, 19:33

It is not possible to move from memory to memory...

15 Mar 2004, 19:33

vid
Verbosity in development

Joined: 05 Sep 2003
Posts: 7105
Location: Slovakia

vid 15 Mar 2004, 20:13

did you check my tuts? There are answers on some of your questions

http://board.flatassembler.net/topic.php?t=1178

15 Mar 2004, 20:13

jInuQ

Joined: 26 Jun 2003
Posts: 48
Location: USA - NV

jInuQ 16 Mar 2004, 08:09

My problem is not moving from memory to memory. As this is not what I am tring to do. I am trying to copy the address of the two pointers in the window_p array.

Code:



; Is this what I am looing for?
mov eax, [window_p]
mov ecx, [window_p+4]

_________________
jInuQ

"Perfection is achieved, not when there is nothing more to add, but when there is nothing left to take away."
- Antoine de Saint Exupery

16 Mar 2004, 08:09

aaro

Joined: 21 Jun 2003
Posts: 107
Location: hel.fi

aaro 16 Mar 2004, 10:08

window_p is pointer to table of to pointers, am i right?
So you have to do it like this:

Code:

mov eax, [window_p]
mov ecx, [eax+4]
mov eax, [eax]

Now eax has value of the first pointer and ecx has the second. Now to modify memory the pointers are pointing to:

Code:

mov [eax], 1
mov [ecx], 2

16 Mar 2004, 10:08

jInuQ

Joined: 26 Jun 2003
Posts: 48
Location: USA - NV

jInuQ 16 Mar 2004, 17:17

Sounds right. Thanks for the help. 8^)

_________________
jInuQ

"Perfection is achieved, not when there is nothing more to add, but when there is nothing left to take away."
- Antoine de Saint Exupery

16 Mar 2004, 17:17

Matrix

Joined: 04 Sep 2004
Posts: 1166
Location: Overflow

Matrix 27 Oct 2004, 13:01

roticv wrote:

It is not possible to move from memory to memory...

yess? why not? Smile

Code:

org 256
push es
push ds
pop es

mov dx,msg
mov ah,9
int 21h

mov di,chgstring
mov si,string2
mov cx,length_string2
call movestring2string

int 21h

pop es
int 20h

movestring2string: ; ds:si > es:di , cx = count
rep
movs byte [es:di],byte [ds:si] ; alternatively : movsb
ret

msg: db 'Hello World!'
chgstring:db 'Is it possible to move string 2 string?',13,10,'$'
string2:  db 'It is possible to move string 2 string!',13,10,'$'
endstring2:
length_string2 dw endstring2-string2

27 Oct 2004, 13:01

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