How does "common" work in macro?

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ntos

Joined: 06 Jul 2023
Posts: 18

ntos 07 Jul 2023, 22:17

Hi,
Here is some code I copied from https://gpfault.net/posts/asm-tut-1.txt.html

Code:

macro foo a, [b, c] {
        common ; we'll explain what "common" means later
                db a, b
                db a, c
        }
        foo 0, 1, 2, 3, 4

This is equivalent to:

Code:

        db 0, 1, 3
        db 0, 2, 4

Can you explain how foo 0,1,2,3,4 could become db 0,1,3? I think it must be db 0,1 and db 0, 2.
Thank you very much.

07 Jul 2023, 22:17

macomics

Joined: 26 Jan 2021
Posts: 949
Location: Russia

macomics 07 Jul 2023, 23:18

1) Comparison of formal and actual parameters: foo a=0, b=1, c=2, b=3, c=4 (or a=0, b=<[0]=1, [1]=3>, c=<[0]=2, [1]=4>)
2) Substitution of formal parameters: db a=0, b=<[0]=1, [1]=3>
db a=0, c=<[0]=2, [1]=4>
3) The list is expanded by the db directive and the sequence is obtained: db 0, 1, 3, 0, 2, 4
4) When using forward or reverse directives, instead of parameters b and c, not lists will be substituted, but a single value with the corresponding index from the list: forward db a, b, c => db a=0, b[0]=1, c[0]=2 => db a=0, b[1]=3, c[1]=4

07 Jul 2023, 23:18

ntos

Joined: 06 Jul 2023
Posts: 18

ntos 08 Jul 2023, 04:54

Thank you very much for your clear answer. The fasm manual must be updated with this answer.

08 Jul 2023, 04:54

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