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flat assembler > Heap > What is the best pie you can get with 9 digits?

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asmhack



Joined: 01 Feb 2008
Posts: 431
revolution wrote:
Yes, okay cr/lf are invisible but they are still needed for the construct to work, and also they are not in the set {0x20..0x7e} so I have to disqualify on technical grounds.


but if you write that on paper you will still have 9 chars Wink
so automatically the limits are disabled because cr/lf is not supported ?
but you said limits are ok..
Post 06 Mar 2008, 14:43
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asmhack



Joined: 01 Feb 2008
Posts: 431
Code:
$FFFFFFFF


Razz
Post 06 Mar 2008, 14:50
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
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Location: M87*
asmhack wrote:
revolution wrote:
Yes, okay cr/lf are invisible but they are still needed for the construct to work, and also they are not in the set {0x20..0x7e} so I have to disqualify on technical grounds.


but if you write that on paper you will still have 9 chars Wink
so automatically the limits are disabled because cr/lf is not supported ?
but you said limits are ok..
Alright, in that case I allow cr/lf not to be counted, but I doubt it will help you. And, yes, limits are supported if you can write it all within 9 ASCII characters (how will you do the right arrow? Wink ).


Last edited by revolution on 06 Mar 2008, 14:53; edited 1 time in total
Post 06 Mar 2008, 14:50
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revolution
When all else fails, read the source


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asmhack wrote:
$FFFFFFFF
and also FFFFFFFFh
Post 06 Mar 2008, 14:52
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asmhack



Joined: 01 Feb 2008
Posts: 431
hahahahaha just details about ~ or -> or whatever..
f*ck that right arrow Razz
Post 06 Mar 2008, 14:56
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asmhack



Joined: 01 Feb 2008
Posts: 431
ok my last attempt:


limx
x->oo

9 chars and not infinite number.. that's why we use limits..


Last edited by asmhack on 06 Mar 2008, 15:30; edited 2 times in total
Post 06 Mar 2008, 15:08
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revolution
When all else fails, read the source


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asmhack wrote:
limx
x->oo
But "oo" is not really the symbol for infinity, is it? Infinity looks like this: ∞, and it isn't ASCII 7bit.
Post 06 Mar 2008, 15:15
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Artlav



Joined: 23 Dec 2004
Posts: 188
Location: Moscow, Russia
revolution wrote:
Artlav wrote:
"n:Vk:n>k"

Where V denotes universal quantifier.
That is, number n, that for any given number k is n>k.
But you haven't really given an actual number or even a description of a number.
I had a strong impression that a description of a number is exactly what i given?
Post 06 Mar 2008, 15:33
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
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Artlav wrote:
revolution wrote:
Artlav wrote:
"n:Vk:n>k"

Where V denotes universal quantifier.
That is, number n, that for any given number k is n>k.
But you haven't really given an actual number or even a description of a number.
I had a strong impression that a description of a number is exactly what i given?
Alright, I may have misunderstood, but it seems you are trying to say that what ever number I can write there is always a larger number. Is that correct?
Post 06 Mar 2008, 15:36
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asmhack



Joined: 01 Feb 2008
Posts: 431
so the conclusion is that the answer is not a limit beacause the shortest thing we can write using limits based on revo's rules is :

lim1/x
x->0

but that is 10 chars.. and i am sure this is not the reason you said 9 chars maximum.. Wink
Post 06 Mar 2008, 15:50
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revolution
When all else fails, read the source


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asmhack wrote:
so the conclusion is that the answer is not a limit ...
Yes, I doubt that limits is the answer. But I would be happy to see a large number using limits (if you can construct it).

Clue: So far, with all the answers given here:

As for ASCII, we have 7/9 of an answer. Of course I won't tell you which parts come from where, but one person has supplied 5/9 on one posting and the other 2/9 supplied by another person in another posting.

As for concepts, we have 1/3 of an answer, so you still need to find two more concepts to build a large number.

Edit: There is actually the germ of the second concept already mentioned, let's call it 1/2 of a concept, so that make 1/3 + 1/2 * 1/3 = 1/2 of the necessary concepts.
Post 06 Mar 2008, 15:58
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bitRAKE



Joined: 21 Jul 2003
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Location: dank orb
1/(0+)

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Post 06 Mar 2008, 16:09
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Borsuc



Joined: 29 Dec 2005
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1/dx Wink
Post 06 Mar 2008, 16:16
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revolution
When all else fails, read the source


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bitRAKE wrote:
1/(0+)
And "0+" is ... ???
Post 06 Mar 2008, 16:22
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asmhack



Joined: 01 Feb 2008
Posts: 431
bitRAKE wrote:
1/(0+)


you can't just use 'your own math rules'.. where is lim ?
Post 06 Mar 2008, 16:22
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revolution
When all else fails, read the source


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The_Grey_Beast wrote:
1/dx
Hmm ...
Post 06 Mar 2008, 16:23
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Borsuc



Joined: 29 Dec 2005
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dx = infinitesmall number (used in integrals and derivatives)
Post 06 Mar 2008, 16:25
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bitRAKE



Joined: 21 Jul 2003
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would you perfer?: 1/(0^+)

I really have to thank this thread for leading me back to the busy beaver function.

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Post 06 Mar 2008, 16:28
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revolution
When all else fails, read the source


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The_Grey_Beast wrote:
dx = infinitesmall number (used in integrals and derivatives)
Yeah I know, but what is the number you are describing?
Post 06 Mar 2008, 16:32
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
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Location: M87*
bitRAKE wrote:
would you perfer?: 1/(0^+)

I really have to thank this thread for leading me back to the busy beaver function.
Your link also says this "... the fraction 1/0 is left undefined ...".
Post 06 Mar 2008, 16:33
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