Why is there no output ?

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Adnarim

Joined: 02 Jan 2007
Posts: 8

Adnarim 03 Jan 2007, 21:29

Hi,
I want to make a loop and wanna print the loopcount on the screen but nothing happens. I debugged the code and see that after the write call, eax is filled with 0xFFFFFF2 which seems to be an error code or?

This is my code:

Code:

section .text
        global _start

_start:
        
        mov ecx,0
label1: inc ecx
        cmp ecx,5
        jne label1
        mov eax,4          
        mov ebx,1  
        mov edx,5  
        int 80h              
        mov eax,1           
        mov ebx,0            
        int 80h

You see a 5 should appear but it doesn't. What is the problem?

03 Jan 2007, 21:29

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4623
Location: Argentina

LocoDelAssembly 03 Jan 2007, 21:54

According to Arafel's system calls reference

Quote:

sys_write [fs/read_write.c]

Writes number of bytes to a device (file, socket, etc.) while advancing the file offset position accordingly.

Arguments

eax 4
ebx Device descriptor.
ecx Pointer to the buffer containing the data to be written.
edx Number of bytes to be written.

So you are requesting to the kernel to write five characters at address 0x00000005 to device 1 (stdout)

03 Jan 2007, 21:54

Adnarim

Joined: 02 Jan 2007
Posts: 8

Adnarim 04 Jan 2007, 15:12

Hey thanks,
I changed the code this way and it works:

Code:

section .text
        global _start

_start:
        mov esi,0
label1: inc esi
        cmp esi,5
        jne label1
        add esi,48
        mov eax,4          
        mov ebx,1
        push esi
        mov ecx,esp       
        mov edx,4
        int 80h              
        mov eax,1           
        mov ebx,0            
        int 80h

But two questions remain: Is there a better or let's say a more general way to convert integer 5 to Char 5 instead of adding 48?

And the other thing is how can I add a newline character to this? So after add esi,48 I have dec 53 = char 5 in esi but how can I add now an newline charachter to this, so that when I print it a newline is shown after that? I know that the dec code is 10 and hex code of the newline feed is A, but how do I use this now?

greets

04 Jan 2007, 15:12

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