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flat assembler
> DOS > Float 16bit? 
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Hehe, if you read my previous post you can atleast see one error in it. I'm trying to represent a double word with 30bits.
What I have learned from this is to never trust Microsoft's calculator as it cuts of ending zeros. The bits should look like this: 00111110001100011101000011001000 If I have understood floating numbers this is how it works. Lets say we have bit 0 to the right and bit 31 to the left. Bit31 = 1 if negative otherwise 0 Bit2330 = Exponent Bit022(23) = Mantissa Bit23 is a very special bit since it being assumed to be 1 when used together with mantissa even if it is 0 in my example above. It is only assumed to be 0 in special cases. The mantissa is represented like this when you calculate it: 1.01100011101000011001000 2^0+0^1+2^2...+0^23 If you want to make it easy on yourself you put everything after the dot in a calculator converts it to decimal and divide it by 2^23 and then add 1. Conclusion: What I tried to represent as a dw was 0.173648 if you do the calculation from my bits above you get. 1*2^(124127)*1.389183=0.1736478. So it seems my previous code was right and Fasm handles my Sin value as single precision. If you would like to know more about float go here http://stevehollasch.com/cgindex/coding/ieeefloat.html Hopefully this helps some confused float newbies as myself. 

24 Oct 2005, 20:34 

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