The "#" on constants names

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LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 16 Aug 2005, 01:45

Why this works

Code:

macro m{
  constant#1 = "H"
}m
display constant1, 13, 10

and this don't work

Code:

constant#1 = "H"
display constant1, 13, 10

?

I'm trying to find a way of generate constants name attaching a number like this:

Code:

macro attach [names]{
common
  num = 1
forward
  names#num = 0
  num = num + 1
}

Of course that code doesn't work, it's only to show what I want, if I do "attach var", I want "var1 = 0" to be defined instead of "varnum = 0".

Please help Sad

16 Aug 2005, 01:45

THEWizardGenius

Joined: 14 Jan 2005
Posts: 382
Location: California, USA

THEWizardGenius 16 Aug 2005, 02:34

Quote:

Why this works

Code:

macro m{ 
  constant#1 = "H" 
}m

display constant1, 13, 10

and this don't work

Code:

constant#1 = "H" 
display constant1, 13, 10

*calls Tomasz* What's up with THIS?

16 Aug 2005, 02:34

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20337
Location: In your JS exploiting you and your system

revolution 16 Aug 2005, 03:12

The '#' only works inside macros (including rept and irp). For your case you will need to use the preprocessor 'rept' to make the labels. Perhaps something like this.

Code:

rept 10 count {names#count=0}

Label names can only be defined during the preprocessor stage. Once the assembly stage has begun only the values of the labes can be changed.

16 Aug 2005, 03:12

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 16 Aug 2005, 15:23

Actually every name will have only one number, for example if I do "attach foo, bar", I'm specting foo1 and bar2 to be defined anymore.

Well I think with your help I will be able to do that now, thank you! Very Happy

16 Aug 2005, 15:23

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20337
Location: In your JS exploiting you and your system

revolution 16 Aug 2005, 16:54

You need to put a double hash, one hash for each level of macro:

Code:

macro attach [names]{
forward
  rept 10 count \{names##count=0\} ;<--- two hashes here
}

attach foo, bar

;display foo+'0', 13, 10           ; Doesn't work
display foo1+'0', 13, 10           ; Works
display bar10+'0', 13, 10          ; Works
;display names5+'0', 13, 10        ; Doesn't work

rept 10 count {constant#count=0}

display constant7+'0', 13, 10      ; Works

16 Aug 2005, 16:54

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 16 Aug 2005, 16:59

No, wait, it doesn't work either Sad

Code:

macro attach [names]{
forward
  rept 10 count \{names#count=0\}
}

attach foo, bar

display foo+'0', 13, 10            ; Doesn't work
display foo1+'0', 13, 10           ; Doesn't work
display bar10+'0', 13, 10          ; Doesn't work
display names5+'0', 13, 10         ; Doesn't work

rept 10 count {constant#count=0}

display constant7+'0', 13, 10      ; Works

16 Aug 2005, 16:59

Tomasz Grysztar

Joined: 16 Jun 2003
Posts: 8353
Location: Kraków, Poland

Tomasz Grysztar 16 Aug 2005, 17:02

Actually according to the current manuals, you should use backslashes to escape the hash as many times as you need, as with any other macro-specific operators. The multiple hashes are kept for backward compatibility, but are no longer documented officially. Wink

16 Aug 2005, 17:02

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 16 Aug 2005, 17:33

Code:

macro attach [names]{
forward
  rept 10 count \{names \# count=count\}
}

Thanks Tomasz Very Happy

16 Aug 2005, 17:33

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 16 Aug 2005, 23:07

Well, after hours of tries I'm still having problems doing this Sad

I need a macro which do the following:

Code:

someMacro 1, 5, 7, 10.5

;At this point I want these numerical constants (not equates) defined and with these values
;value1 = 1
;value2 = 5
;value3 = 7
;value4 = 10.5

I can't find a way to do that Sad

16 Aug 2005, 23:07

Reverend

Joined: 24 Aug 2004
Posts: 408
Location: Poland

Reverend 16 Aug 2005, 23:56

Code:

        irps count, 1 2 3 4 5 6 7 8 9 10
         { foo # count = count }

16 Aug 2005, 23:56

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 17 Aug 2005, 00:36

Reverend, it doesn't works either. I need every constant with the values passed to the macro, not "fooX = X".

Another example:

Code:

someMacro 10, 7.2, aConstant

; At this point I need EXACTLY these constants defined with those values:

;foo1 = 10
;foo2 = 7.2
if foo3 = aConstant
  display "OK, the macro works!!",13,10
end if

I need something like "foo # paramNumber = paramValue", where foo is always "foo", paramNumber goes from 1 to 3 and paramValue 10, 7.2, aConstant when I call the macro with this "someMacro 10, 7.2, aConstant".

17 Aug 2005, 00:36

UCM

Joined: 25 Feb 2005
Posts: 285
Location: Canada

UCM 17 Aug 2005, 01:06

oh, btw you mean:
if foo3 eq aConstant
not
if foo3 = aConstant
cause it woudn't be valid, = is for assigning constants.

_________________
This calls for... Ultra CRUNCHY Man!
Ta da!! *crunch*

17 Aug 2005, 01:06

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 17 Aug 2005, 01:11

UCM, "if foo3 = aConstant" is valid, check it with this if you want:

Code:

foo = 4
bar = 5

if foo = bar
  display "foo = 5",13,10
end if
bar = bar - 1
if foo = bar
  display "foo = 4",13,10
end if

BTW, aConstant is a numerical constant like the others.

17 Aug 2005, 01:11

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 20337
Location: In your JS exploiting you and your system

revolution 17 Aug 2005, 01:18

Code:

macro bar name,[count,value] {forward name#count=value}
bar foo,1,1,2,5,3,7,4,10
bar foo,1,10,2,7.2,3,aConstant

BUt I think you want automatic numbering? I'm not sure if it is possible to get the numbering automatic, perhaps it is but I can't see how. But the above macro will do the job for you if you put the numbering manually.

17 Aug 2005, 01:18

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 17 Aug 2005, 01:48

revolution wrote:

BUt I think you want automatic numbering?

Yes, you are right, I need automatic and always from 1 to count. Thanks for post that code, I didn't know that the macros with [x,y] were possible.

17 Aug 2005, 01:48

UCM

Joined: 25 Feb 2005
Posts: 285
Location: Canada

UCM 17 Aug 2005, 02:09

Oh, well maybe I'm getting rather mixed up.

_________________
This calls for... Ultra CRUNCHY Man!
Ta da!! *crunch*

17 Aug 2005, 02:09

Tomasz Grysztar

Joined: 16 Jun 2003
Posts: 8353
Location: Kraków, Poland

Tomasz Grysztar 17 Aug 2005, 09:42

One of possible solutions is:

Code:

macro someMacro [val]
 { common
    counter equ 1
   forward
    match current,counter ; this we need to get value of counter before preprocessing
    \{
       value \# current = val
       rept 2 i:current \\{ counter equ i \\} ; this increases the counter
    \}
 }

someMacro 1,5,7,10.5 ; it defines value1=1, value2=5, etc.

17 Aug 2005, 09:42

Madis731

Joined: 25 Sep 2003
Posts: 2139
Location: Estonia

Madis731 17 Aug 2005, 10:01

On a side-topic about constants:
Is there a way to visually unpack bits and FASM still generates:

Code:

mov eax,1000 0000b

Of course FASM gives error here, but what can delete the extra spaces for FASM to assemble?

17 Aug 2005, 10:01

LocoDelAssembly
Your code has a bug

Joined: 06 May 2005
Posts: 4624
Location: Argentina

LocoDelAssembly 17 Aug 2005, 11:27

Excelent Tomasz, thank you!!!

Just another question, why only works with "rept 2"? I can't see why is needed repeat 2 times "counter equ i".
[edit]I know now, the first time "counter EQU i" and the second time "counter EQU (i+1)", sorry Embarassed

[/edit]

17 Aug 2005, 11:27

vid
Verbosity in development

Joined: 05 Sep 2003
Posts: 7105
Location: Slovakia

vid 17 Aug 2005, 19:12

grrr, i was going to make same solution as privalov but i forgot to escape # operator... grrr, i could have been first Smile

))

17 Aug 2005, 19:12

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