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flat assembler > Compiler Internals > Strangeness with xor operator in constants expression

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bazizmix



Joined: 15 Jan 2016
Posts: 37
flat assembler version 1.72
Simple text:
Code:
ZZZ equ 1
mov eax,-1 xor ZZZ
mov eax,ZZZ xor -1    

and produced code:
Code:
B8 00 00 00 00 | mov eax,0         <-- wrong
B8 FE FF FF FF | mov eax,FFFFFFFE  <-- right    

But!!!
Code:
ZZZ equ 2
mov eax,-1 xor ZZZ
mov eax,ZZZ xor -1    

all OK:
Code:
B8 FD FF FF F | mov eax,FFFFFFFD
B8 FD FF FF F | mov eax,FFFFFFFD     
Post 04 Feb 2018, 12:30
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revolution
When all else fails, read the source


Joined: 24 Aug 2004
Posts: 16057
Location: 112 Ocean Avenue, Amityville
Unary minus has a lower precedence than xor. You can put brackets around the leading minus to force what you need.
Code:
mov eax,(-1) xor ZZZ    


Last edited by revolution on 04 Feb 2018, 13:48; edited 1 time in total
Post 04 Feb 2018, 13:03
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bazizmix



Joined: 15 Jan 2016
Posts: 37
Thanks, revolution!
Post 04 Feb 2018, 13:27
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