What is the best pie you can get with 9 digits?

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revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

You are allowed a maximum of nine ASCII characters (0x20-0x7e) only, this includes spaces and brackets etc., to write a representation of a number.

All standard mathematical symbols and functions etc. are allowed.

So I will start the ball rolling with:

"9+9+9+9+9"

But I'm sure you can do better.

Last edited by revolution on 09 Jan 2017, 19:18; edited 2 times in total

06 Mar 2008, 03:09

sinsi

Joined: 10 Aug 2007
Posts: 688
Location: Adelaide

sinsi

999999999

or something like 1e9999999

?

too bad there's not an infinity key... Laughing

06 Mar 2008, 03:17

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

sinsi wrote:

too bad there's not an infinity key...

infinity is not a number anyway, so even if there was an infinity key it wouldn't count Wink

06 Mar 2008, 04:00

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

sinsi wrote:

999999999

sinsi wrote:

1e9999999

Accept

Can anyone do better?

06 Mar 2008, 04:01

sinsi

Joined: 10 Aug 2007
Posts: 688
Location: Adelaide

sinsi

factorial? 99999999!
powers? 9^9^9^9^9 (might need brackets though)

The largest named number is googolplex - 10^googol (hah! 9 chars)

06 Mar 2008, 04:39

bitRAKE

Joined: 21 Jul 2003
Posts: 2800
Location: dank orb

bitRAKE

9^9^9^9^9 is a large number

Edit: ah, ya beat me to it Smile

How about 99^googol then

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Last edited by bitRAKE on 06 Mar 2008, 04:44; edited 1 time in total

06 Mar 2008, 04:42

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

sinsi wrote:

99999999!

sinsi wrote:

9^9^9^9^9 (might need brackets though)

Accept. Without brackets use standard parsing to get the value

sinsi wrote:

10^googol

Accept

Can anyone do better?

Last edited by revolution on 06 Mar 2008, 04:46; edited 1 time in total

06 Mar 2008, 04:42

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

bitRAKE wrote:

9^9^9^9^9 is a large number

Too late, sinsi beat you to it.

06 Mar 2008, 04:44

bitRAKE

Joined: 21 Jul 2003
Posts: 2800
Location: dank orb

bitRAKE

factorials!:

9^googol!
9!!!!!!!!

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06 Mar 2008, 04:48

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

bitRAKE wrote:

9^googol!

bitRAKE wrote:

9!!!!!!!!

Accept, but not very big, multifactorials are maybe not what you expect.

06 Mar 2008, 04:51

bitRAKE

Joined: 21 Jul 2003
Posts: 2800
Location: dank orb

bitRAKE

Thanks for the link, superfactorial then:
9$$$$$$$$

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06 Mar 2008, 04:54

sinsi

Joined: 10 Aug 2007
Posts: 688
Location: Adelaide

sinsi

Nice link, how about a hyperfactorial - H(999999)

Wow, this is getting too esoteric for me...

06 Mar 2008, 05:00

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

bitRAKE wrote:

9$$$$$$$$

Accept, (but what is the order of evaluation? I also don't know)

Can anyone do better?

06 Mar 2008, 05:01

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

sinsi wrote:

H(999999)

Accept, but smaller than 9$$$$$$$$

Can anyone do better?

06 Mar 2008, 05:02

Tomasz Grysztar
Assembly Artist

Joined: 16 Jun 2003
Posts: 7498
Location: Kraków, Poland

Tomasz Grysztar

9($^9$$$)

the ^ applied to operator means the composition (so 9($^8)=9$$$$$$$$)

or even...

G($^G$$$)

06 Mar 2008, 06:08

DOS386

Joined: 08 Dec 2006
Posts: 1903

DOS386

-ln(0)
abs(1/0)
(1/0)^2
ta2(pi/2)
ro90("8")

Crying or Very sad

Last edited by DOS386 on 06 Mar 2008, 06:21; edited 3 times in total

06 Mar 2008, 06:13

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

Tomasz Grysztar wrote:

9($^9$$$)

Accept, but not with the explanation below, only accept for ^=power, in which case it doesn't make sense really, but the syntax is allowed

Tomasz Grysztar wrote:

the ^ applied to operator means the composition (so 9($^8)=9$$$$$$$$)

Not accept, I don't think this is standard, you are not allowed to make up your own definition of symbols.

Tomasz Grysztar wrote:

G($^G$$$)

edit: Accept Graham's number.

Last edited by revolution on 08 Mar 2008, 13:28; edited 2 times in total

06 Mar 2008, 06:15

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

DOS386 wrote:

-ln(0)
abs(1/0)
(1/0)^2
ta2(pi/2)

All not accept, results are undefined, or infinity, and thus not numbers.

06 Mar 2008, 06:17

Tomasz Grysztar
Assembly Artist

Joined: 16 Jun 2003
Posts: 7498
Location: Kraków, Poland

Tomasz Grysztar

revolution wrote:

Not accept, I don't think this is standard, you are not allowed to make up your own definition of symbols.

It is standard to denote the repeated function composition in the same way as a power of number, see functional powers. I explained what it means just in case someone didn't know it, I didn't "make up my own definition".

06 Mar 2008, 06:23

revolution
When all else fails, read the source

Joined: 24 Aug 2004
Posts: 16904
Location: In your JS exploiting you and your system

revolution

Tomasz Grysztar wrote:

revolution wrote:
Not accept, I don't think this is standard, you are not allowed to make up your own definition of symbols.

It is standard to denote the repeated function composition in the same way as a power of number, see functional powers.

Okay then, I accept, but it doesn't feel right to me.

But it doesn't matter really, because, so far, no one has come even close to putting a REALLY big number.

06 Mar 2008, 06:28

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